A is twice as efficient as B. Working together, they finish a job in 24 days. How many days would A take to finish the job alone?

💡 Solution & Explanation

If B does 1 unit of work per day, A does 2 units, so together they do 3 units per day. The whole job is 3 × 24 = 72 units. A alone takes 72 ÷ 2 = 36 days, and B alone would take 72 days. A, being faster, needs fewer days than B but more than the 24 days they take together.