What happens to the terminal velocity of a small spherical body falling through a viscous fluid if its radius is doubled?

💡 Solution & Explanation

According to Stokes' law, terminal velocity is directly proportional to the square of the radius of a spherical body falling through a viscous medium, meaning doubling the radius multiplies the velocity by four. Linear proportionality or inverse relations do not apply here since viscous drag depends on both surface area and velocity gradients.