MasteryExams
Quantitative Aptitude • Number System & SimplificationHard

What is the smallest number greater than 15 which, when divided by 6, 9 and 15, leaves a remainder of 3 in each case?

A. 90
B. 183
C. 87
D. 93✓ Correct Answer

💡 Solution & Explanation

A number that leaves the same remainder 3 with each divisor is (a common multiple of 6, 9 and 15) + 3. The smallest common multiple is the LCM: LCM(6, 9) = 18 and LCM(18, 15) = 90. So the number is 90 + 3 = 93. (3 itself also leaves remainder 3, but it is not greater than 15.) Check: 93 ÷ 6 leaves 3, ÷ 9 leaves 3, and ÷ 15 leaves 3.

🚩 Report a problem