What volume of carbon dioxide gas is liberated at standard temperature and pressure when exactly 10 grams of calcium carbonate is thermally decomposed completely, given the molar mass of calcium carbonate is 100 grams per mole and molar volume of gas at STP is 22.4 liters?

💡 Solution & Explanation

Thermal decomposition of calcium carbonate produces calcium oxide and one mole of carbon dioxide gas per mole of reactant. Ten grams of calcium carbonate corresponds to 0.1 moles. According to stoichiometry, 0.1 moles of calcium carbonate will produce 0.1 moles of carbon dioxide gas. Multiplying 0.1 moles by the molar volume of 22.4 liters per mole at STP yields 2.24 liters of carbon dioxide gas. Molar mass calculations are fundamental for quantitative chemical analysis.