A body falls freely from rest under gravity. What is the ratio of distances covered by the body in the first, second, and third seconds of its motion?

💡 Solution & Explanation

The distance covered by a freely falling body in the nth second is given by the formula s equals acceleration due to gravity divided by two multiplied by the quantity two times n minus one. Substituting n values of one, two, and three yields distances proportional to one, three, and five respectively. The total distance covered in time t is proportional to the square of the time elapsed.